Question:
Combine three resistors 5Ω , 4.5Ω and 3Ω in such a way that the total resistance of this combination is maximum with value
(Α) 12.5 Ω
(Β) 13.5 Ω
(C) 14.5 Ω
(D) 16.5 Ω
Answer:
(Α) 12.5 Ω
Explanation:
To find the combination of resistors that yields the maximum total resistance, we should connect them in series. In a series connection, resistances simply add up.
The total resistance \( R_{total} \) in a series connection is given by the sum of individual resistances:
\[ R_{total} = R_1 + R_2 + R_3 \]
Given resistances:
\[ R_1 = 5Ω \]
\[ R_2 = 4.5Ω \]
\[ R_3 = 3Ω \]
\[ R_{total} = 5Ω + 4.5Ω + 3Ω \]
\[ R_{total} = 12.5Ω \]
So, the total resistance when the resistors are combined in series is \( 12.5Ω \), which matches option (A). Therefore, the correct answer is (Α) 12.5 Ω.